CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    In the figure shown below, the terminal voltage across\[{{E}_{2}}\]is

    A)  12V    

    B)                                         12.66V

    C)  11.34V                

    D)         11.66V

    E)  12.33V

    Correct Answer: C

    Solution :

    Net voltage \[=12-8=4\text{ }V\] Net resistance \[=9+2+1=12\,\Omega \] Current through the circuit\[=\frac{4}{12}=\frac{1}{3}A\] Terminal voltage across\[{{E}_{2}}\]is                 \[={{E}_{2}}-I{{r}_{2}}=12-\frac{1}{3}\times 2\]                 \[=12-\frac{2}{3}=\frac{34}{3}=11.34\,V\]


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