A) 2
B) 3
C) 1
D) 5
E) 4
Correct Answer: B
Solution :
\[f=\frac{v}{4l}\]or\[l=\frac{v}{4f}\] \[\therefore \] \[{{l}_{1}}=\frac{v}{4{{f}_{1}}}=\frac{330}{4\times 500}=0.165\,m;\] \[{{l}_{2}}=\frac{3v}{4{{f}_{1}}}=3{{l}_{1}}=0.495;\] \[{{l}_{3}}=\frac{5v}{4{{f}_{1}}}=5{{l}_{1}}=0.825\,m\] And \[{{l}_{4}}=\frac{7v}{4{{f}_{1}}}=7{{l}_{1}}=1.155>1\,m\] Therefore, number of resonance = 3.You need to login to perform this action.
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