A) 48.8 mH
B) 200 mH
C) 187.5 mH
D) 320 mH
E) 78.1 mH
Correct Answer: D
Solution :
Self-inductance \[L=\frac{{{\mu }_{0}}{{N}^{2}}A}{L}\] \[\Rightarrow \] \[L\propto {{N}^{2}}\] Or \[\frac{{{L}_{2}}}{{{L}_{1}}}={{\left( \frac{{{N}_{2}}}{{{N}_{1}}} \right)}^{2}}\] Or \[{{L}_{2}}={{L}_{1}}{{\left( \frac{{{N}_{2}}}{{{N}_{1}}} \right)}^{2}}=125{{\left( \frac{800}{500} \right)}^{2}}=320\,mH\]
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