A)
Geometrical Optical 6 2
B)
Geometrical Optical 4 2
C)
Geometrical Optical 6 0
D)
Geometrical Optical 4 0
E)
Geometrical Optical 5 2
Correct Answer: A
Solution :
The acyclic stereoisomers of\[{{C}_{4}}{{H}_{7}}Cl\]are \[\left. C{{H}_{2}}=CH-\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{{{C}^{*}}}}}\,-C{{H}_{3}} \right\}2\,optical\,isomers.\] Number of optical isomers \[={{2}^{n}}={{2}^{1}}=2\] Hence, total number of geometrical isomers\[=6\] Total number of optical isomers\[=2\]You need to login to perform this action.
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