A) \[f(x)=\sin x,x\in [-\pi ,\pi ]\]
B) \[f(x)=\sin x,x\in \left[ -\frac{3\pi }{2},-\frac{\pi }{4} \right]\]
C) \[f(x)=\cos x,x\in \left[ -\frac{\pi }{2},\frac{\pi }{2} \right]\]
D) \[f(x)=\cos x,x\in [\pi ,2\pi )\]
E) \[f(x)=\cos x,x\in \left[ -\frac{\pi }{4},\frac{\pi }{4} \right]\]
Correct Answer: D
Solution :
In the given options (a), (b), (c), (e) the curves are decreasing and increasing in the given intervals, so it is not one-to-one function. But in option (d), the curve is only increasing in the given intervals, so it is one-to-one function.You need to login to perform this action.
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