A) \[{{H}_{2}}{{O}_{2}}\]
B) \[N{{a}_{2}}O\]
C) \[N{{a}_{2}}O\]and\[{{O}_{3}}\]
D) \[NaOH\]and\[N{{a}_{2}}C{{O}_{3}}\]
E) \[NaOH\]and\[{{H}_{2}}{{O}_{2}}\]
Correct Answer: D
Solution :
Sodium peroxide reacts with moisture and\[C{{O}_{2}}\]of air (when exposed to air) and becomes white due to the formation of\[NaOH\]and\[N{{a}_{2}}C{{O}_{3}}\] \[2N{{a}_{2}}{{O}_{2}}+2{{H}_{2}}O\xrightarrow{{}}4NaOH+{{O}_{2}}\] \[2NaOH+C{{O}_{2}}\xrightarrow{{}}N{{a}_{2}}C{{O}_{3}}+{{H}_{2}}O\]
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