A) \[(2x+y)\]
B) \[(x+y)\]
C) \[(2x/y)\]
D) \[(y-2x)\]
E) \[(2x-y)\]
Correct Answer: D
Solution :
Given \[S(rh)+\frac{3}{2}{{O}_{2}}(g)\xrightarrow[{}]{{}}S{{O}_{3}}(g);\] \[\Delta H=-2x\,kJ\,mo{{l}^{-1}}\] ...(i) \[S{{O}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow[{}]{{}}S{{O}_{3}}(g);\] \[\Delta H=-y\,kJ\,mo{{l}^{-1}}\] ...(ii) \[S(s)+{{O}_{2}}(g)\xrightarrow{{}}S{{O}_{2}}(g);\] \[\Delta H=?\] Subtract Eq (ii) from Eq (i) \[S(rh)+\frac{3}{2}{{O}_{2}}(g)\xrightarrow{{}}S{{O}_{3}}(g);\] \[\Delta H=-2x\text{ }kJ\text{ }mo{{l}^{-1}}\] \[S{{O}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}S{{O}_{3}}(g);\] \[\Delta H=-y\,kJ\,mo{{l}^{-1}}\] \[\underline{-\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\,\,\,\,\,\,\,\,}\] \[S(rh)+\left( \frac{3}{2}-\frac{1}{2} \right){{O}_{2}}(g)\xrightarrow{{}}S{{O}_{2}}(g);\]\[\Delta H=(-2x+y)\] \[kJ\,mo{{l}^{-1}}\] \[S(rh)+{{O}_{2}}(g)\xrightarrow[{}]{{}}S{{O}_{2}}(g);\] \[\Delta H=(y-2x)kJ\,mo{{l}^{-1}}\]
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