question_answer

Match List-1 and List-11 and choose the correct matching codes.

List - I	List - II
(A) \[{{[Ni{{(CN)}_{4}}]}^{2-}}\]	1. \[T{{i}^{4+}}\]
(B) Chlorophyll	2.\[s{{p}^{3}};\]paramagnetic
(C) Ziegler - Natta catalyst	3. non-planar
(D) \[{{[NiC{{l}_{4}}]}^{2-}}\]	4. \[M{{g}^{2+}}\]
(E) Deoxyhaemoriobin	5. Planar
	6.\[ds{{p}^{2}};\] diamagnetic

               

A)                 A-6         B-4         C-1         D-2         E-3

B)                 A-2         B-4         C-1         D-6         E-3

C)                 A-2         B-4         C-1         D-6         E-5

D)                 A-6         B-4         C-1         D-2         E-5

E)                  A-2        B-4         C-3         D-6         E-5

Correct Answer: A

Solution :

(a) \[{{[Ni{{(CN)}_{4}}]}^{2-}}\] \[Ni(28)=[Ar]\,3{{d}^{8}}4{{s}^{2}}\] \[N{{i}^{2+}}=[Ar]\,3{{d}^{8}},4s\] Since,\[C{{N}^{-}}\]is a strong field ligand, it causes pairing of electrons. (b) Chlorophyll contains\[M{{g}^{2+}}\]ion. (c) Ziegler-Natta catalyst is\[T{{i}^{4+}}+{{({{C}_{2}}{{H}_{5}})}_{3}}Al\]. (d) \[{{[NiC{{l}_{4}}]}^{2-}}\] In this case,\[C{{l}^{-}}\]is a weak field ligand, so does not couse pairing. Hence, Due to the presence of unpaired electrons, it is paramagnetic. (e) Deoxyhaemoglobin is non-planar while oxyhaemoglobin is planar. Hence, the correct matching is as \[A-6;B-4;C-1;D-2;E-3\]