List - I | List - II |
(A) \[{{[Ni{{(CN)}_{4}}]}^{2-}}\] | 1. \[T{{i}^{4+}}\] |
(B) Chlorophyll | 2.\[s{{p}^{3}};\]paramagnetic |
(C) Ziegler - Natta catalyst | 3. non-planar |
(D) \[{{[NiC{{l}_{4}}]}^{2-}}\] | 4. \[M{{g}^{2+}}\] |
(E) Deoxyhaemoriobin | 5. Planar |
6.\[ds{{p}^{2}};\] diamagnetic |
A) A-6 B-4 C-1 D-2 E-3
B) A-2 B-4 C-1 D-6 E-3
C) A-2 B-4 C-1 D-6 E-5
D) A-6 B-4 C-1 D-2 E-5
E) A-2 B-4 C-3 D-6 E-5
Correct Answer: A
Solution :
(a) \[{{[Ni{{(CN)}_{4}}]}^{2-}}\] \[Ni(28)=[Ar]\,3{{d}^{8}}4{{s}^{2}}\] \[N{{i}^{2+}}=[Ar]\,3{{d}^{8}},4s\] Since,\[C{{N}^{-}}\]is a strong field ligand, it causes pairing of electrons. (b) Chlorophyll contains\[M{{g}^{2+}}\]ion. (c) Ziegler-Natta catalyst is\[T{{i}^{4+}}+{{({{C}_{2}}{{H}_{5}})}_{3}}Al\]. (d) \[{{[NiC{{l}_{4}}]}^{2-}}\] In this case,\[C{{l}^{-}}\]is a weak field ligand, so does not couse pairing. Hence, Due to the presence of unpaired electrons, it is paramagnetic. (e) Deoxyhaemoglobin is non-planar while oxyhaemoglobin is planar. Hence, the correct matching is as \[A-6;B-4;C-1;D-2;E-3\]You need to login to perform this action.
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