A) 1, 4-diiodobutane
B) 1, 4-butanediol
C) 2-iodotetrahydrofuran
D) 4-iodo-l-butanol
E) 2, 5-diiodotetrahydrofuran
Correct Answer: A
Solution :
Tetrahydrofuran when treated with excess\[HI,\]gives 1, 4-diiodobutane.
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