A) \[4\sqrt{10}\]
B) \[40\]
C) \[\sqrt{40}\]
D) \[10\sqrt{2}\]
E) \[2\sqrt{20}\]
Correct Answer: C
Solution :
Let equation of line parallel to\[3x-y=7\]be\[3x-y=\lambda \]. It passes through (1, 2). \[\therefore \] \[3-2=\lambda \Rightarrow \lambda =1\] \[\therefore \]Line is \[3x-y=1\] The point of intersection of\[x+y+5=0\]and \[3x-y-1\]is\[(-1,-4)\]. \[\therefore \]Distance between (1, 2) and\[(-1,-4)\] \[=\sqrt{{{(2)}^{2}}+{{(6)}^{2}}}=\sqrt{40}\]You need to login to perform this action.
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