A) \[\frac{1}{10}\]
B) \[\frac{1}{4}\]
C) \[\frac{1}{55}\]
D) \[\frac{7}{12}\]
E) \[\frac{3}{4}\]
Correct Answer: C
Solution :
As we know, the sum of probability density function is one. \[\therefore \]\[p(X={{x}_{1}})+p(X={{x}_{2}})+...+p(X={{x}_{10}})=1\] \[\Rightarrow \] \[1k+2k+3k+....+10k=1\] \[\Rightarrow \] \[\frac{10(10+1)}{2}k=1\] \[\Rightarrow \] \[k=\frac{1}{55}\]You need to login to perform this action.
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