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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    A block of mass m is resting on a smooth horizontal surface. One end of a uniform rope of mass\[\left( \frac{m}{3} \right)\]is fixed to the block, which is pulled in the horizontal direction by applying force F at the other end. The tension in the middle of the rope is

    A)  \[\frac{8}{7}F\]               

    B)         \[\frac{1}{7}F\]

    C)  \[\frac{1}{8}F\]               

    D)         \[\frac{1}{5}F\]

    E)  \[\frac{7}{8}F\]

    Correct Answer: E

    Solution :

    Acceleration of the system \[a=\frac{F}{\left( m+\frac{m}{3} \right)}\] \[\therefore \]Tension in the middle of the rope                 \[t=\left( M+\frac{M}{6} \right)a\] Or           \[T=\frac{7m}{6}.\frac{3F}{4m}\] Or           \[T=\frac{7}{8}F\]


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