A) \[C{{H}_{3}}{{(C{{H}_{2}})}_{3}}Br\]
B) \[C{{H}_{3}}{{(C{{H}_{2}})}_{2}}CH(Br)C{{H}_{2}}C{{H}_{3}}\]
C) \[C{{H}_{3}}{{(C{{H}_{2}})}_{3}}CH(Br)C{{H}_{3}}\]
D) \[C{{H}_{3}}{{(C{{H}_{2}})}_{5}}Br\]
E) \[C{{H}_{3}}Br\]
Correct Answer: B
Solution :
Since, the alkyl halide RX gives 4, 5-diethyloctane, when reacts with Na, it must be\[C{{H}_{3}}{{(C{{H}_{2}})}_{2}}CH(Br)C{{H}_{2}}C{{H}_{3}}.\] \[2C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}\underset{\begin{smallmatrix} | \\ C{{H}_{2}}C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-Br\xrightarrow[Dry\,ether]{Na}\] \[C{{H}_{3}}{{(C{{H}_{2}})}_{2}}\overset{\begin{smallmatrix} C{{H}_{2}}C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{CH}}\,-\overset{\begin{smallmatrix} \,\,\,\,\,\,C{{H}_{2}}C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{CH}}\,-{{(C{{H}_{2}})}_{2}}\,-C{{H}_{3}}\] This reaction is known as Wurtz reaction.
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