CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    If\[{{\cos }^{-1}}\left( \frac{5}{13} \right)-{{\sin }^{-1}}\left( \frac{12}{13} \right)={{\cos }^{-1}}x,\]then\[x\]is equal to

    A)  \[1\]    

    B)  \[\frac{1}{\sqrt{2}}\]

    C)  \[0\]                    

    D)         \[\frac{\sqrt{3}}{2}\]

    E)  \[-1\]

    Correct Answer: A

    Solution :

    Given, \[{{\cos }^{-1}}\left( \frac{5}{13} \right)-{{\sin }^{-1}}\left( \frac{12}{13} \right)={{\cos }^{-1}}x\] \[\Rightarrow \]\[{{\sin }^{-1}}\left( \frac{12}{13} \right)-{{\sin }^{-1}}\left( \frac{12}{13} \right)={{\cos }^{-1}}x\] \[\Rightarrow \]               \[{{\cos }^{-1}}x=0\Rightarrow \cos 0\] \[\Rightarrow \]               \[x=1\]                


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