A) \[\frac{25}{6}\]
B) \[\frac{25}{12}\]
C) \[\frac{5}{6}\]
D) \[\frac{17}{12}\]
E) \[6\]
Correct Answer: B
Solution :
The intersection points of given lines are \[(0,0),\left( \frac{5}{2},5 \right),\left( \frac{5}{3},5 \right)\] \[\therefore \]0 Area of\[\Delta =\frac{1}{2}\left| \begin{matrix} 0 & 0 & 1 \\ \frac{5}{2} & 5 & 1 \\ \frac{5}{3} & 5 & 1 \\ \end{matrix} \right|\] \[=\frac{1}{2}\left[ 1\left( \frac{25}{2}-\frac{25}{3} \right) \right]\] \[=\frac{1}{2}\times \frac{25}{6}\] \[=\frac{25}{12}sq\,unit\]
You need to login to perform this action.
You will be redirected in
3 sec
