CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    The vertices of a triangle are (3, 0), (3, 3) and (0, 3). Then, the coordinates of the circumcentre are

    A)  (0, 0)                    

    B)         (1, 1)

    C)  \[\left( \frac{5}{2},\frac{5}{2} \right)\]           

    D)         (2, 2)

    E)  \[\left( \frac{3}{2},\frac{3}{2} \right)\]

    Correct Answer: E

    Solution :

    Given vertices are the vertices of right angled triangle with\[\angle C=\frac{\pi }{2}\]. \[\therefore \]Coordinates of the circumcentre is the midpoint of AB ie, \[\left( \frac{3}{2},\frac{3}{2} \right)\].


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