A) \[x+y=0\]
B) \[x-y=0\]
C) \[3x+y=0\]
D) \[x+3y=0\]
E) \[x+2y=0\]
Correct Answer: D
Solution :
Centre of given circle is\[(3,-1)\]. As we know that diameter of a circle is passing through centre of circle. In the given options centre lies on the line \[x+3y=0\]
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