CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    If Q is the image of the point P(2, 3, 4) under the reflection in the plane\[x-2y+5z=6,\]then the equation of the line PQ is

    A)  \[\frac{x-2}{-1}=\frac{y-3}{2}=\frac{z-4}{5}\]

    B)  \[\frac{x-2}{1}=\frac{y-3}{-2}=\frac{z-4}{5}\]

    C)  \[\frac{x-2}{-1}=\frac{y-3}{-2}=\frac{z-4}{5}\]

    D)  \[\frac{x-2}{1}=\frac{y-3}{2}=\frac{z-4}{5}\]

    E)  None of the above

    Correct Answer: B

    Solution :

    Since, point Q is the image of P, therefore PQ is perpendicular to the plane\[x-2y+5z=6\] \[\therefore \]Required equation of line is \[\frac{x-2}{1}=\frac{y-3}{-2}=\frac{z-4}{5}\]


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