A) \[\frac{1}{2}\]
B) 1
C) \[\frac{3}{2}\]
D) 2
E) 0
Correct Answer: C
Solution :
Given, \[f\{f(x)\}=x+1\] ...(i) \[\therefore \] \[f(f(0))=0+1\] \[\Rightarrow \] \[f\left( \frac{1}{2} \right)=1\] \[\left[ \because f(0)=\frac{1}{2} \right]\] Now, put\[x=\frac{1}{2}\]in Eq. (i), we get \[f\left\{ f\left( \frac{1}{2} \right) \right\}=\frac{1}{2}+1\] \[\Rightarrow \] \[f(1)=\frac{3}{2}\]You need to login to perform this action.
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