A) \[\frac{297}{4}\]
B) \[\frac{3}{2}\sqrt{33}\]
C) \[\frac{3}{2}\sqrt{99}\]
D) \[\sqrt{\frac{99}{12}}\]
E) \[\frac{3\sqrt{3}}{2}\]
Correct Answer: B
Solution :
Given, \[\sigma _{10}^{2}=\frac{99}{12}=\frac{33}{4}\] \[\Rightarrow \] \[{{\sigma }_{10}}=\frac{\sqrt{33}}{2}\] SD of required series\[=3{{\sigma }_{10}}\] \[=\frac{3\sqrt{33}}{2}\]
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