A) (2, 1, 3)
B) (6, 7, 8)
C) (4, 1, 3)
D) (7, 7, 7)
E) (8, 8, 8)
Correct Answer: D
Solution :
Let the vertices of a parallelogram are A(1, 1, 1) B(1, 3, 5), C(7, 9, 11) and fourth vertex be D (\[x\], y, z) Midpoint of AC is (4, 5, 6) and midpoint of BD is\[\left( \frac{1+x}{2},\frac{3+y}{2},\frac{5+z}{2} \right)\]. In a parallelogram midpoint of diagonals are coincide. \[\therefore \] \[\frac{1+x}{2}=4,\frac{3+y}{2}=5,\frac{5+z}{2}=6\] \[\Rightarrow \] \[x=7,y=7,z=7\]You need to login to perform this action.
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