A) \[\frac{49}{4}\]
B) \[\frac{53}{9}\]
C) \[\frac{53}{7}\]
D) \[\frac{49}{9}\]
E) \[\frac{45}{7}\]
Correct Answer: B
Solution :
Given, \[f(x)={{(x-7)}^{2}}{{(x-2)}^{7}}\] \[\Rightarrow \] \[f(\theta )={{(\theta -7)}^{2}}{{(\theta -2)}^{7}}\] \[\Rightarrow \]\[f(\theta )=2(\theta -7){{(\theta -2)}^{7}}+7{{(\theta -2)}^{6}}{{(\theta -7)}^{2}}\] Put \[f(\theta )=0\] \[\Rightarrow \]\[(\theta -7){{(\theta -2)}^{6}}[2(\theta -2)+7(\theta -7)]=0\] \[\Rightarrow \]\[9\theta =53\Rightarrow \theta =\frac{53}{9}\]You need to login to perform this action.
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