CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    \[\int{(\sqrt[3]{x})}\left( \sqrt[3]{1+\sqrt[3]{{{x}^{4}}}} \right)dx\]is equal to

    A)  \[{{\left( 1+{{x}^{\frac{3}{4}}} \right)}^{\frac{5}{6}}}+c\]              

    B)  \[{{\left( 1+{{x}^{\frac{4}{3}}} \right)}^{\frac{5}{6}}}+c\]

    C)  \[\frac{5}{8}{{\left( 1+{{x}^{\frac{4}{3}}} \right)}^{\frac{6}{5}}}+c\]

    D)         \[\frac{1}{6}{{\left( 1+{{x}^{\frac{4}{3}}} \right)}^{6}}+c\]

    E)  \[\frac{15}{8}{{\left( 1+{{x}^{\frac{4}{3}}} \right)}^{\frac{6}{5}}}+c\]

    Correct Answer: C

    Solution :

    Let\[I=\int{\sqrt[3]{x}}(\sqrt[5]{1+\sqrt[3]{{{x}^{4}}}})dx\] Put            \[\sqrt[3]{{{x}^{4}}}=t\] \[\Rightarrow \]               \[\frac{4}{3}.\sqrt[3]{x}dx=dt\] \[\therefore \]  \[I=\frac{3}{4}\int{(\sqrt[5]{1+t})dt}\]                 \[=\frac{3}{4}\left[ \frac{{{(1+t)}^{\frac{1}{5}+1}}}{\frac{1}{5}+1} \right]+c\]                 \[=\frac{5}{8}[{{(1+\sqrt[3]{{{x}^{4}}})}^{6/5}}]+c\]


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