CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    The centre of a regular hexagon is at the point\[z=i\]. If one of its vertices is at\[2+i,\]then the adjacent vertices of\[2+i\]are at the points

    A)  \[1\pm 2i\]

    B)  \[i+1\pm \sqrt{3}\]

    C)  \[2+i(1\pm \sqrt{3})\]

    D)  \[1+i(1\pm \sqrt{3})\]

    E)  \[1-i(1\pm \sqrt{3})\]

    Correct Answer: D

    Solution :

    Given, \[z=i\] Let \[{{z}_{1}}+1+i(1\pm \sqrt{3})\] and\[{{z}_{2}}=2+i\] Now,     \[|{{z}_{2}}-z|=|2+i-i|\]                 \[=2\] As we know that the distance from the centre to every vertices is equal. Now,     \[|{{z}_{1}}-z|=|1+i(1\pm \sqrt{3})-i|\]                 \[=|1\pm i\sqrt{3}|=\sqrt{{{1}^{2}}+{{(\sqrt{3})}^{2}}}\] \[=2\] Hence, option (d) is correct.


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