CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    The value of\[\frac{1}{2!}+\frac{2}{3!}+....+\frac{999}{1000!}\]is equal to

    A)  \[\frac{1000!-1}{1000!}\]

    B)                         \[\frac{1000!+1}{1000!}\]

    C)  \[\frac{999!-1}{999!}\] 

    D)         \[\frac{999!+1}{999!}\]

    E)  \[\frac{1000!-999!}{1000!}\]

    Correct Answer: A

    Solution :

    \[\frac{1}{2!}+\frac{2}{3!}+....+\frac{999}{1000!}\] \[=\frac{2-1}{2!}+\frac{3-1}{3!}+.....+\frac{1000-1}{1000!}\] \[=\frac{1}{1!}+\frac{1}{2!}+\frac{1}{2!}-\frac{1}{3!}+....+\frac{1}{999!}-\frac{1}{1000!}\] \[=1-\frac{1}{1000!}=\frac{1000!-1}{1000!}\]


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