A) \[\frac{3}{4}\]
B) \[\frac{7}{8}\]
C) \[\frac{1}{4}\]
D) \[1\]
E) \[\frac{1}{8}\]
Correct Answer: A
Solution :
The moment of inertia of circular ring \[=M{{R}^{2}}\] The moment of inertia of removed sector \[=\frac{1}{4}M{{R}^{2}}\] The moment of inertia of remaining part \[=M{{R}^{2}}-\frac{1}{4}M{{R}^{2}}\] \[=\frac{3}{4}M{{R}^{2}}\] According to question, the moment of inertia of the remaining part \[=kM{{R}^{2}}\] then \[k=\frac{3}{4}\]You need to login to perform this action.
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