A) 4s
B) 6s
C) 5s
D) 2.5s
E) 4.5s
Correct Answer: C
Solution :
Given: \[MI=2.5\text{ }kg\text{ }{{m}^{-2}}\] \[\omega =40\text{ }rad\text{ }{{s}^{-1}}\] \[\tau =10\text{ }Nm\] As \[\tau =I\alpha \] \[\therefore \] \[10=2.5\alpha \] \[\alpha =4\text{ }rad\text{ }{{s}^{-2}}\] Now, \[\omega ={{\omega }_{0}}+\alpha t\] \[\therefore \] \[60=40+4\times t\] or \[20=4t\] \[t=5s\]You need to login to perform this action.
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