CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    A particle of mass m carrying charge q is kept at rest in a uniform electric field E and then released. The kinetic energy gained by the particle, when it moves through a distance y is.

    A)  \[\frac{1}{2}qE{{y}^{2}}\]           

    B)         \[qEy\]

    C)  \[qE{{y}^{2}}\]

    D)         \[q{{E}^{2}}y\]

    E)  \[{{q}^{2}}Ey\]

    Correct Answer: B

    Solution :

    Kinetic energy = work done \[=F.d\] \[=qE\times y\] \[=qEy\]


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