A) 1A and\[3\mu C\]
B) 17 A and \[0\mu C\]
C) \[\frac{6}{7}A\] and\[\frac{12}{7}\mu C\]
D) 6 A and\[0\mu C\]
E) \[11A\] and\[3\mu C\]
Correct Answer: E
Solution :
In steady state current through the branch having capacitor is zero. \[\therefore \] \[\frac{1}{R}=\frac{1}{1}+\frac{1}{2}+\frac{1}{3}\] \[\frac{1}{R}=\frac{6+3+2}{6}\] \[R=\frac{6}{11}\] As \[V=iR\] \[\therefore \] \[6=i\times \frac{6}{11}\] Current through the battery \[i=11\text{ }A\] Charge on the capacitor \[q=CV\] \[\Rightarrow \] \[q=0.5\times {{10}^{-6}}\times 6\] \[q=3\mu C\]
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