CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    Two different conductors have same resistance at\[{{0}^{o}}C\]. It is found that the resistance of the first conductor at\[{{t}_{1}}^{o}C\]is equal to the resistance of the second conductor at\[{{t}_{2}}^{o}C\]. The ratio of the temperature coefficients of resistance of the conductors,\[\frac{{{\alpha }_{1}}}{{{\alpha }_{2}}}\]is

    A)  \[\frac{{{t}_{1}}}{{{t}_{2}}}\]                     

    B)         \[\frac{{{t}_{2}}-{{t}_{1}}}{{{t}_{2}}}\]

    C)  \[\frac{{{t}_{2}}-{{t}_{1}}}{{{t}_{1}}}\]   

    D)         \[\frac{{{t}_{2}}}{{{t}_{1}}}\]

    E)  \[\frac{{{t}_{2}}}{{{t}_{2}}-{{t}_{1}}}\]

    Correct Answer: D

    Solution :

    Resistance of a conductor varies linearly with temperature as \[{{R}_{t}}={{R}_{0}}(1+\alpha t)\] for first conductor                 \[{{R}_{t}}={{R}_{0}}(1+{{\alpha }_{1}}{{t}_{1}})\] or          \[{{\alpha }_{1}}=\frac{R{{t}_{1}}-{{R}_{0}}}{{{t}_{1}}}\]                   ?? (i) Similarly, for second conductor \[{{\alpha }_{2}}=\frac{R{{t}_{2}}-{{R}_{0}}}{{{t}_{2}}}\]                                 ?.. (ii) From Eqs. (i) and (ii) we get                 \[\frac{{{\alpha }_{1}}}{{{\alpha }_{2}}}=\frac{{{t}_{2}}}{{{t}_{1}}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner