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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    A potentiometer wire of length 10 m and resistance\[20\,\Omega \]is connected in series with a 15 V battery and an external resistance\[40\,\Omega \]. A secondary cell of emf£ in the secondary circuit is balanced by 240 cm long potentiometer wire. The emf E of the cell is

    A)  2.4 V              

    B)         1.2 V

    C)  2.0 V                    

    D)  3 V

    E)  6 V

    Correct Answer: B

    Solution :

    Total resistance or            \[R=20+40\] \[R=60\Omega .\] Given:      \[V=15\]volt current    \[I=\frac{V}{R}=\frac{15}{60}\]   \[I=0.25\text{ }A\] Potential gradient \[=\frac{V}{l}\]                                 \[\frac{20\times 0.25}{10}\] \[=0.5V{{m}^{-1}}\] Potential difference across 240 cm                 \[E=0.5\times 2.4\]                 \[E=1.2\,V\]


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