A) \[10\,V\]
B) \[\frac{20}{\sqrt{2}}\,V\]
C) \[20\sqrt{2}\,V\]
D) \[\frac{10}{\sqrt{2}}\,V\]
E) \[20\,V\]
Correct Answer: D
Solution :
Circuit is resonant, hence supply voltage equals to\[{{V}_{R}}\]. \[{{V}_{R}}=10\]volt Also, \[{{X}_{C}}=R\] As the voltage drops are equals across L, C and R then when L is short \[Z=\sqrt{{{R}^{2}}+X_{C}^{2}}\] \[=\sqrt{2}R\] \[{{V}_{C}}=i{{X}_{C}}\] \[\left[ \because i=\frac{V}{Z} \right]\] Or \[{{V}_{C}}=\frac{V}{Z}{{X}_{C}}\] Or \[=\frac{10}{\sqrt{2}R}R\] Or \[{{V}_{C}}=\frac{10}{\sqrt{2}}volt\]
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