A) \[60\,\Omega \]
B) \[50\,\Omega \]
C) \[80\,\Omega \]
D) \[100\,\Omega \]
E) \[120\,\Omega \]
Correct Answer: D
Solution :
\[\eta =\frac{output\text{ }power}{input\text{ }power}=\frac{{{V}_{S}}{{I}_{S}}}{4000}=\frac{Z{{({{I}_{S}})}^{2}}}{4000}\] \[\therefore \] \[\frac{90}{100}=\frac{Z{{(6)}^{2}}}{4000}\] or \[Z=100\,\Omega \]
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