A) 2H
B) 8H
C) 20 H
D) 10 H
E) 5H
Correct Answer: D
Solution :
\[U=\frac{1}{2}L{{I}^{2}}\] \[\therefore \] \[\frac{du}{dt}=\frac{1}{2}L.2I\frac{dI}{dt}\] \[\therefore \] \[D=LI\frac{dI}{dt}\] \[\therefore \] \[L=\frac{P}{I\frac{dI}{dt}}=\frac{\left( \frac{1}{2} \right)}{0.1\times 0.5}=10\,H\]You need to login to perform this action.
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