CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    The refractive index and the permeability of a medium are respectively 1.5 and\[5\times {{10}^{-7}}H{{M}^{-1}}\]. The relative permittivity of the medium is nearly

    A)  25                         

    B)         15

    C)  81                         

    D)         10

    E)  6

    Correct Answer: E

    Solution :

    Given refractive index \[n=1.5\] Permeability \[{{\mu }_{0}}=5\times {{10}^{-7}}H{{m}^{-1}}\]                                 \[n=\sqrt{{{\mu }_{r}}{{\varepsilon }_{r}}}\]                                 \[{{\varepsilon }_{r}}=\frac{{{n}^{2}}}{{{\mu }_{r}}}\] Or           \[{{\varepsilon }_{r}}=\frac{{{n}^{2}}{{\mu }_{0}}}{\mu }\]                           \[\left[ \because {{\mu }_{r}}=\frac{\mu }{{{\mu }_{0}}} \right]\] Or           \[{{\varepsilon }_{r}}=\frac{{{(1.5)}^{2}}\times 4\pi \times {{10}^{-7}}}{5\times {{10}^{-7}}}\] Or           \[{{\varepsilon }_{r}}=6\]            


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