CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    A square wire of side 1 cm is placed perpendicular to the principal axis of a concave mirror of focal length 15 cm at a distance of 20 cm. The area enclosed by the image of the wire is

    A)  \[4c{{m}^{2}}\]               

    B)         \[6c{{m}^{2}}\]

    C)  \[2c{{m}^{2}}\]               

    D)         \[8c{{m}^{2}}\]

    E)  \[9c{{m}^{2}}\]

    Correct Answer: E

    Solution :

    Given focal length of concave mirror \[f=-15cm\] \[u=-20\text{ }cm\] Magnification \[m=\frac{f}{u-f}\]                                 \[=\frac{-15}{-20+15}\]                                 \[m=3\,cm\] The area enclosed by the image of the wire \[={{m}^{2}}\] \[=9\text{ }cm\]


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