A) \[4\lambda \]
B) \[3.5\lambda \]
C) \[3\lambda \]
D) \[2.75\lambda \]
E) \[2.5\lambda \]
Correct Answer: A
Solution :
\[\frac{hc}{\lambda }-\frac{\lambda c}{{{\lambda }_{0}}}=3\] ...(i) \[\frac{hc}{\lambda }-\frac{hc}{{{\lambda }_{0}}}=1\] Dividing Eq. (i) by Eq. (ii) \[\frac{\frac{1}{\lambda }-\frac{1}{{{\lambda }_{0}}}}{\frac{1}{2\lambda }-\frac{1}{{{\lambda }_{0}}}}=3\] \[\frac{2({{\lambda }_{0}}-\lambda )}{{{\lambda }_{0}}-2\lambda }=3\] \[2{{\lambda }_{0}}-2\lambda =3{{\lambda }_{0}}-6\lambda \] \[{{\lambda }_{0}}=4\lambda \]
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