A) \[{{A}_{0}}\]
B) \[\frac{2}{3}{{A}_{0}}\]
C) \[\frac{{{A}_{0}}}{9}\]
D) \[\frac{{{A}_{0}}}{6}\]
E) \[\frac{{{A}_{0}}}{18}\]
Correct Answer: C
Solution :
The original activity of radioactive element is\[{{A}_{0}}\]. Two-third of the original activity decreases in a period of 9 yr. Now, original activity \[=\frac{{{A}_{0}}}{3}\] After a further lapse of 9 yr its activity becomes \[=\frac{1}{3}\times \frac{{{A}_{0}}}{3}\] \[=\frac{{{A}_{0}}}{9}\]
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