A) \[{{I}^{-}}\]
B) \[CO_{3}^{2-}\]
C) \[{{S}^{2-}}\]
D) \[NO_{2-}^{{}}\]
E) \[C{{l}^{-}}\]
Correct Answer: B
Solution :
In\[CO_{3}^{2-},\]C is present in its highest oxidation state, ie, +4 state, so its further oxidation is not possible, it only undergoes reduction. Acidified\[KMn{{O}_{4}}\]is a strong oxidizing agent, but it cannot oxidize\[CO_{3}^{2-}\]. Hence, it will not be decolorized by\[CO_{3}^{2-}\].You need to login to perform this action.
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