A) Na and\[N{{a}_{2}}{{O}_{2}}\]
B) \[Ca\]and\[Ca{{H}_{2}}\]
C) Ca and CaO
D) Ba and\[Ba{{O}_{2}}\]
E) Ca and\[Ca{{C}_{2}}\]
Correct Answer: B
Solution :
The given substances react with water in the following manner \[Na+{{H}_{2}}O\xrightarrow{{}}NaOH+{{H}_{2}}(g)\] \[2N{{a}_{2}}{{O}_{2}}+2{{H}_{2}}O\xrightarrow{{}}4NaOH+{{O}_{2}}(g)+{{H}_{2}}(g)\] \[Ca+{{H}_{2}}O\xrightarrow{{}}CaO+{{H}_{2}}\] \[Ca{{H}_{2}}+2{{H}_{2}}O\xrightarrow[{}]{{}}Ca{{(OH)}_{2}}+2{{H}_{2}}\] \[CaO+{{H}_{2}}O\xrightarrow[{}]{{}}Ca{{(OH)}_{2}}\] \[Ca{{C}_{2}}+2{{H}_{2}}O\xrightarrow{{}}Ca{{(OH)}_{2}}+{{C}_{2}}{{H}_{2}}\] \[Ba+2{{H}_{2}}O\xrightarrow{{}}Ba{{(OH)}_{2}}+{{H}_{2}}\] \[Ba{{O}_{2}}+{{H}_{2}}O\xrightarrow{{}}B{{a}^{2+}}+{{O}_{2}}+{{H}_{2}}{{O}_{2}}\] Hence,\[Ca\]and\[Ca{{H}_{2}}\]is the pair that gives same gaseous product on reaction with water.
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