question_answer

Concentrated sulphuric acid can be reduced by

A) \[NaCl\]              

B) \[NaF\]

C) \[NaOH\]            

D)        \[NaN{{O}_{3}}\]

E) \[NaBr\]

Correct Answer: E

Solution :

Concentrated sulphuric acid, being a strong acid, oxidizes bromides and iodides but not chlorides and fluorides since, the later are more electronegative. Hence, it can be reduced only by\[NaBr\]among the given options. \[\overset{+6}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,+\overset{-1}{\mathop{NaBr}}\,\xrightarrow{{}}Na\overset{+6}{\mathop{HS{{O}_{4}}}}\,+\overset{-1}{\mathop{HBr}}\,\]