A) \[NaCl\]
B) \[NaF\]
C) \[NaOH\]
D) \[NaN{{O}_{3}}\]
E) \[NaBr\]
Correct Answer: E
Solution :
Concentrated sulphuric acid, being a strong acid, oxidizes bromides and iodides but not chlorides and fluorides since, the later are more electronegative. Hence, it can be reduced only by\[NaBr\]among the given options. \[\overset{+6}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,+\overset{-1}{\mathop{NaBr}}\,\xrightarrow{{}}Na\overset{+6}{\mathop{HS{{O}_{4}}}}\,+\overset{-1}{\mathop{HBr}}\,\]You need to login to perform this action.
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