question_answer

In the following reaction, \[{{M}^{x+}}+MnO_{4}^{-}\xrightarrow{{}}MO_{3}^{-}+M{{n}^{2+}}+\frac{1}{2}{{O}_{2}},\] If one mole of\[MnO_{4}^{-}\]oxidizes 2.5 moles of\[{{M}^{x+}},\]then the value of\[x\]is

A) 5                                             

B) 3

C) 2                             

D)        1

E) 4

Correct Answer: B

Solution :

\[x+2=5\] \[\therefore \]  \[x=5-2=+3\]