A) \[dH=TdS+Vdp\]
B) \[dH=SdT+Vdp\]
C) \[dH=-SdT+Vdp\]
D) \[dH=dE+pdV\]
E) \[dH=dE-TdS\]
Correct Answer: A
Solution :
Given, \[dE=TdS-pdV\] ...(i) \[H=E+pV\] ...(ii) Differentiating Eq. (ii), \[dH=dE+pdV+vdp\] ...(iii) From Eq. (i) and (iii), we get \[dH=TdS+vdp\]You need to login to perform this action.
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