A) \[+1\text{ }V\]
B) \[-0.6\text{ }V\]
C) zero
D) \[-\,12V\]
E) \[+12\text{ }V\]
Correct Answer: C
Solution :
Current \[i=\frac{{{V}_{1}}-{{V}_{2}}}{{{R}_{1}}+{{R}_{2}}}=\frac{18}{1.2\times {{10}^{-6}}}\] V across \[1\,M\Omega =\frac{18}{1.2\times {{10}^{-6}}}\times 1\times {{10}^{-6}}\] \[=15\,V\] \[\therefore \]Potential at \[P=15-15=0\]You need to login to perform this action.
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