A) \[0.4\,\Omega \]
B) \[0.3\,\,\Omega \]
C) \[1.2\,\Omega \]
D) \[0.2\,\,\Omega \]
E) \[0.1\,\Omega \]
Correct Answer: E
Solution :
Resistance of galvanometer, \[{{R}_{1}}=100\text{ }\Omega \] Connected resistance, \[{{R}_{2}}=10\text{ k}\Omega =10000\,\Omega \] Total resistance, \[R=10000+100\] \[=10100\,\Omega \] Current of galvanometer, \[{{i}_{g}}=\frac{V}{R}\] \[=\frac{10}{10100}\] \[=9.9\times {{10}^{-4}}\] \[\approx 10\times {{10}^{-4}}A\] Shunt, \[S=\frac{{{i}_{g}}}{i-{{i}_{g}}}\times 100\] \[=\frac{{{i}_{g}}}{(1-10\times {{10}^{-4}})}\times 100\] \[=\frac{100}{0.99}\times 10\times {{10}^{-4}}=0.1\,\Omega \]You need to login to perform this action.
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