A) 0.25mA
B) 0.05mA
C) 0.12mA
D) 0.02mA
E) 0.07mA
Correct Answer: B
Solution :
\[{{i}_{C}}{{R}_{C}}={{V}_{C}}\] \[{{i}_{C}}=\frac{{{V}_{C}}}{{{R}_{C}}}=\frac{0.6}{600}=1\,mA\] \[\therefore \] \[\beta =\frac{{{i}_{C}}}{{{i}_{B}}}\] Or \[{{i}_{B}}=\frac{{{i}_{C}}}{\beta }=\frac{1}{20}=0.05\,mA\]You need to login to perform this action.
You will be redirected in
3 sec