CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    If\[|\overrightarrow{a}|=5,|\overrightarrow{b}|=6\]and\[\overrightarrow{a}.\overrightarrow{b}=-25,\]then\[|\overrightarrow{a}\times \overrightarrow{b}|\]is equal to

    A)  25                                         

    B)  \[6\sqrt{11}\]

    C)  \[11\sqrt{5}\]                  

    D)         \[11\sqrt{6}\]

    E)  \[5\sqrt{11}\]

    Correct Answer: D

    Solution :

    Given, \[|\overrightarrow{a}|=5,|\overrightarrow{b}|=6,\overrightarrow{a}.\overrightarrow{b}=-25\] \[\therefore \]\[\cos \theta =\frac{\overrightarrow{a}.\overrightarrow{b}}{|\overrightarrow{a}|.|\overrightarrow{b}|}=\frac{-25}{5\times 6}=-\frac{25}{30}=-\frac{5}{6}\] \[\therefore \]\[\sin \theta =\sqrt{1-{{\cos }^{2}}\theta }=\sqrt{1-\frac{25}{36}}\]                 \[=\sqrt{\frac{11}{36}}\] \[\therefore \]  \[|\overrightarrow{a}\times \overrightarrow{b}|=|\overrightarrow{a}|\,|\overrightarrow{b}|\sin \theta |\]                 \[=5\times 6\times \sqrt{\frac{11}{36}}\]                 \[=5\sqrt{11}\]


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