A) 25
B) 9
C) 4
D) 5
E) 16
Correct Answer: B
Solution :
The given equation of ellipse is \[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{16}=1\] Comparing it with \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\] \[\Rightarrow \] \[a=5,b=4\] and centre of ellipse = (0, 0) \[\therefore \]Maximum distance of CP \[=\sqrt{{{(5-0)}^{2}}+{{(0-0)}^{2}}}=5\] and minimum distance of CP \[=\sqrt{{{(0-0)}^{2}}+{{(4-0)}^{2}}}=4\] \[\therefore \] Sum \[=5+4=9\]You need to login to perform this action.
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